Mark Houwink Sakurada Equation

Mark-Houwink-Sakurada Equation | Polymer Chemistry

IIT-JAM │ GATE │ CSIR-NET │ TIFR │ BARC │ Polymer Chemistry

Statement

A polymer's intrinsic viscosity ([η]) is related to its molecular weight (M) by constants (K and a) specific to the polymer-solvent system and temperature, allowing for polymer characterization by determining molecular weight from viscosity or vice versa, with 'a' indicating polymer shape (e.g., random coil, rigid rod).

[η] = K Mᵃ

where
[η] = Intrinsic viscosity (dL/g or cm³/g)
M = Viscosity-average molecular weight (Mᵥ)
K and a = Mark-Houwink constants (depend on polymer, solvent & temperature)

Logarithmic Form (Most Used in Numericals)

log[η] = log K + a log M

Physical Significance of Exponent ‘a’

Value of ‘a’Chain ConformationExample System
0 Hard sphere (no solvent effect)
0.5 Theta solvent (ideal chain, Flory condition)PS in cyclohexane at 34°C
0.5 – 0.8 Good solvent (random coil, expanded chain)Most polymers in good solvents
0.8 Theoretical maximum for random coil
1.0 – 1.8 Rigid rodDNA, poly(isocyanates), xanthan
> 1.8 Not possible for flexible chains

Typical Values of K and a (Important for Exams)

PolymerSolventTemp (°C)K × 10⁵ (dL/g)a
PolystyreneToluene257.5 – 160.71 – 0.74
PolystyreneCyclohexane (theta)34840.50
Poly(methyl methacrylate)Acetone257.70.70
PolyethyleneDecalin135670.67
DNA (double helix)Aqueous buffer251.0 – 1.7

Applications (Repeatedly Asked)

  • Determination of viscosity-average molecular weight Mᵥ from single [η] measurement
  • Quick estimation of molecular weight in industry
  • Study of polymer–solvent interaction (value of ‘a’)
  • Theta solvent identification (a = 0.5)
  • Conformational analysis (coil ↔ rod)

Limitations

  • Valid only in a certain molecular weight range (usually 10⁴ – 10⁶)
  • K and a are specific to polymer + solvent + temperature
  • Not applicable for polyelectrolytes without salt
  • Gives Mᵥ, not Mₙ or Mₓ (Mₙ ≤ Mᵥ ≤ Mₓ)

High-Yield Exam Questions

1. The exponent ‘a’ in Mark-Houwink equation is 0.5 for a polymer in
Answer: Theta solvent
2. For a rigid rod-like polymer, the value of ‘a’ lies in the range
Answer: 1.0 – 1.8 (commonly 1.7–1.8)
3. If [η] = 1.2 dL/g for a polymer sample and K = 1.0 × 10⁻⁴ dL/g, a = 0.7, then Mᵥ ≈
(Calculation: log 1.2 = log(10⁻⁴) + 0.7 log M → M ≈ 1.58 × 10⁵ g/mol)
Answer: ≈ 1.6 × 10⁵ g/mol
4. Assertion: In a good solvent, the intrinsic viscosity of a polymer increases with molecular weight more rapidly than in a theta solvent.
Reason: In good solvent, the exponent ‘a’ > 0.5.
Answer: Both A and R are true and R is correct explanation of A
5. The molecular weight obtained from Mark-Houwink equation is
Answer: Viscosity-average molecular weight (Mᵥ)
MPSET 2024
6. The intrinsic viscosity (η) of a polymer solution is related with molecular weight (M) of the polymer (k and a are constants):
A. η = kMa
B. η = kM1/a
C. η = 1/akM
D. η = kaM
Answer: η = kMa
X

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