Write the hydrolysis products of XeF2, XeF4 and XeF6 and discuss the factors which affects the hydrolysis.
Hydrolysis of Xenon Fluorides
The process of hydrolysis of xenon fluoride involves a number of intermediates and can be carried out in a multiple pathways. The initial formation of a xenon-oxygen bond, followed by the subsequent release of hydrogen fluoride is an essential reaction pathway. Hydrolysis of different xenon fluorides are given below-
Hydrolysis of XeO2
2XeF2 (s) + 2H2O(l) → 2Xe (g) + 4 HF(aq) + O2(g)Hydrolysis of XeO4
6XeF4 + 12 H2O → 4Xe + 2XeO3 + 24 HF + 3O2Hydrolysis of XeO6
XeF6 + 3 H2O → XeO3 + 6 HFPartial hydrolysis of XeF6 gives oxyfluorides,
XeF6 + H2O → XeOF4 + 2HF
XeF6 + 2 H2O → XeO2F2 + 4HF
Factors Affecting Hydrolysis
The rate and extent of hydrolysis of xenon fluorides are affected by several factors. Some of them are given below-
Identity of xenon fluoride: Different xenon fluorides exhibit different reactivity towards hydrolysis. Generally, higher the oxidation state of xenon, higher the reactivity.
Concentration of Water: Higher the concentration of water, faster will be the rate of hydrolysis.
Temperature: Higher the temperatures, faster the hydrolysis reaction.
pH: pH of the reaction medium affects the hydrolysis pathway and generate certain xenon-oxygen species.
The end product of the complete hydrolysis of XeF6 is
A. XeOF4
B. XeO2F2
C. XeO3
D. XeO3−
Answer
Option C is correct answer.
Complete hydrolysis of XeF6 gives one molecule of XeO3 and six molecules of Hydrogen fluoride.
XeF6 + 3 H2O → XeO3 + 6 HF