Classification of Molecular Rotors in Rotational Spectroscopy
Important for: CSIR-NET, GATE, SET, and other competitive exams.
The rotation of a three dimensional body may be quite complex and it is convenient to resolve it into rotational components about three mutually perpendicular direction through the centre of gravity - the principal axes of rotation. Thus a body has three principal moments of inertia, one about each axis, usually Ia, Ib, and Ic.
Molecules are classified as rigid rotors based on their three principal moments of inertia (Ia, Ib, Ic), conventionally ordered as Ia ≤ Ib ≤ Ic. Rotational constants are defined as A = h/(8π²c Ia), B = h/(8π²c Ib), C = h/(8π²c Ic) in cm⁻¹ (A ≥ B ≥ C).
Summary Table
| Type | Moments of Inertia | Rotational Constants | Energy Levels (Rigid Rotor) | Examples | Microwave Spectrum |
|---|---|---|---|---|---|
| Linear Molecules | Ia ≈ 0, Ib = Ic | A >> B = C | EJ = B J(J+1) (hc cm⁻¹) | CO2, HC≡CH, OCS, HCl, CO | Yes (if μ ≠ 0) |
| Symmetric Tops | Two equal | Two equal | EJ,K = B J(J+1) + (A - B) K² | See sub-types | Yes (if μ along symmetry axis) |
| • Prolate | Ia < Ib = Ic | A > B = C | E = B J(J+1) + (A - B) K² | CH3Cl, CH3CN, CH3F | |
| • Oblate | Ia = Ib < Ic | A = B > C | E = B J(J+1) + (C - B) K² | BF3, NH3, C6H6 | |
| Spherical Tops | Ia = Ib = Ic | A = B = C | EJ = B J(J+1) | CH4, SF6, CCl4 | No (μ = 0; weak due to distortion) |
| Asymmetric Tops | Ia ≠ Ib ≠ Ic | A > B > C | No closed form; numerical (Wang basis) | H2O, H2CO, NO2, CH3OH | Yes (complex spectrum) |
1. Linear Molecules
- Atoms arranged linearly; rotation about bond axis has negligible moment of inertia (Ia ≈ 0).
- Treated as rigid rotor with single rotational constant B.
- Energy levels: F(J) = BJ(J+1) (in cm⁻¹)
- Degeneracy: (2J+1)
- Selection rule: ΔJ = ±1 → lines at 2B(J+1)
- Non-polar (e.g., CO2, N2) show no pure rotational spectrum.
2. Symmetric Tops
- Two moments equal; possess C3 or higher symmetry axis.
- Quantum numbers: J (total angular momentum), K (projection along symmetry axis, |K| ≤ J).
- Energy levels: F(J,K) = BJ(J+1) + (A-B)K²
- Degeneracy: (2J+1) for K=0; 2(2J+1) for K≠0
- Selection rules: ΔJ = ±1, ΔK = 0
- Spectrum similar to linear molecules (spacing 2B).
Prolate Symmetric Tops
- Cigar-shaped; symmetry axis has smaller inertia.
- Ia < Ib = Ic → A > B = C
- Examples: CH3F, CH3Cl, CH3C≡CH
Oblate Symmetric Tops
- Disc-shaped; symmetry axis has larger inertia.
- Ia = Ib < Ic → A = B > C
- Examples: NH3, BF3, benzene (C6H6)
3. Spherical Tops
- All moments equal; high symmetry (tetrahedral/octahedral).
- Energy: F(J) = BJ(J+1)
- Degeneracy: (2J+1)2
- No permanent dipole → no pure rotational microwave spectrum (weak lines due to centrifugal distortion).
- Examples: CH4, SF6, SiH4, OsO4, CCl4
4. Asymmetric Tops
- All three moments different; most molecules belong here.
- No analytical energy expression; use basis of symmetric top functions and diagonalize Hamiltonian.
- Ray's asymmetry parameter κ = (2B - A - C)/(A - C) (-1 for prolate limit, +1 for oblate limit).
- Complex spectra; near-symmetric cases approximate symmetric top behavior.
- Examples: H2O (near prolate), H2CO, SO2, CH3OH, CH3=CH-Cl
Practice Exam Questions (MCQs)
Suitable for CSIR-NET, GATE, SET, JAM, etc.
1. Which of the following molecules is classified as a spherical top rotor?
Answer: (c) CH4
Explanation: Spherical tops have Ia = Ib = Ic (e.g., tetrahedral/octahedral symmetry). CH4 is tetrahedral.
Explanation: Spherical tops have Ia = Ib = Ic (e.g., tetrahedral/octahedral symmetry). CH4 is tetrahedral.
2. Linear molecules are considered as a special case of:
Answer: (b) Prolate symmetric top
Explanation: In linear molecules, Ia ≈ 0 → A → ∞, making it an extreme prolate case (A >> B = C).
Explanation: In linear molecules, Ia ≈ 0 → A → ∞, making it an extreme prolate case (A >> B = C).
3. Which molecule will NOT show a pure rotational microwave spectrum?
Answer: (c) CO2
Explanation: CO2 is linear but non-polar (μ = 0). Pure rotational transitions require a permanent dipole moment.
Explanation: CO2 is linear but non-polar (μ = 0). Pure rotational transitions require a permanent dipole moment.
4. Benzene (C6H6) is an example of:
Answer: (b) Oblate symmetric top
Explanation: Planar hexagonal structure → I⊥ (out-of-plane) smaller than in-plane → oblate (A = B > C).
Explanation: Planar hexagonal structure → I⊥ (out-of-plane) smaller than in-plane → oblate (A = B > C).
5. The Ray's asymmetry parameter κ is +1 for:
Answer: (b) Oblate symmetric top
Explanation: κ = (2B - A - C)/(A - C); κ → -1 (prolate limit), κ → +1 (oblate limit).
Explanation: κ = (2B - A - C)/(A - C); κ → -1 (prolate limit), κ → +1 (oblate limit).
6. For a prolate symmetric top, the rotational energy is given by:
Answer: (b) BJ(J+1) + (A - B)K²
Explanation: Standard expression for prolate (A > B = C).
Explanation: Standard expression for prolate (A > B = C).
7. Spherical top molecules show very weak or no microwave absorption primarily because:
Answer: (b) They lack a permanent dipole moment
Explanation: High symmetry (e.g., Td, Oh) results in μ = 0.
Explanation: High symmetry (e.g., Td, Oh) results in μ = 0.
8. Which of the following is an asymmetric top?
Answer: (c) SO2
Explanation: Bent structure → all three moments of inertia different.
Explanation: Bent structure → all three moments of inertia different.
9. The rotational spectrum of symmetric tops appears similar to that of linear molecules because:
Answer: (b) and (d)
Explanation: ΔK = 0 → transitions depend only on J → spacing 2B, independent of K.
Explanation: ΔK = 0 → transitions depend only on J → spacing 2B, independent of K.
10. Methyl chloride (CH3Cl) is a:
Answer: (c) Prolate symmetric top
Explanation: C3v symmetry, elongated along C–Cl axis → Ia < Ib = Ic.
Explanation: C3v symmetry, elongated along C–Cl axis → Ia < Ib = Ic.