Chemistry of Phosphazenes

Phosphazenes - Complete Notes for JEE Adv • JAM • GATE • CSIR-NET

PHOSPHAZENES (PN Compounds)
Inorganic Polymers & Heterocycles

JEE Advanced │ IIT-JAM │ GATE │ CSIR-NET │ IISc │ TIFR │ BARC

1. Introduction

  • Phosphazenes are inorganic heterocyclic/polymeric compounds containing alternating P and N atoms with general formula (NPX2)n
  • Backbone: –P=N–P=N– (similar to siloxane –Si–O–Si–O–)
  • Also called phosphonitrilic compounds
  • Most important examples: cyclic trimer (X2P=N)3 and tetramer (X2P=N)4, and linear high polymers [NPX2]n

2. Preparation of Cyclic Phosphazenes

n PCl5 + n NH4Cl → [NPCl2]n + 4n HCl

Most common reaction (in chlorobenzene or tetrachloroethane at 130–140°C)
Gives mixture of cyclic trimer (n=3), tetramer (n=4) and higher polymers

(NPCl2)3 and (NPCl2)4 can be prepared by ammonolysis of PCl5
3PCl5 + 3NH3 → (NPCl2)3 + 9HCl
4PCl5 + 4NH3 → (NPCl2)4 + 12HCl

Separation: Trimer & tetramer are distilled out; high polymer remains as rubbery mass

3. Important Cyclic Phosphazenes

NameFormulaStructurePhysical State
Hexachlorocyclotriphosphazene(NPCl2)36-membered ringColourless crystalline solid
Octachlorocyclotetraphosphazene(NPCl2)48-membered ringWhite solid
High polymer[NPCl2]nLinear/cross-linkedRubbery elastomer

Structure of Common Chlorocyclophosphazenes
Most important & most asked: (NPCl2)3 – called phosphonitrilic chloride trimer

4. Structure & Bonding

  • All rings are planar
  • P–N bond length ≈ 158 pm (intermediate between single & double bond)
  • Bonding explained by three theories (very important for CSIR-NET):
    1. Island model (Dewar) → dπ–pπ bonding + hyperconjugation
    2. Three-centre four-electron bonds (heteromorphic bonding)
    3. Polarised π-bonding
  • All P atoms are sp³ hybridised while N atoms are sp²
  • Delocalised 6π or 8π electrons in cyclic systems → aromatic character
structure of Phosphazenes

5. Reactions of (NPCl2)3 & (NPCl2)4 (Substitution Reactions)

All six/eight Cl atoms are highly reactive and can be replaced step-wise:

(NPCl2)3 + 6 NaOR → (NPRO2)3 + 6 NaCl
(NPCl2)3 + 6 NH3 → (NPNH2)3 + 6 HCl
(NPCl2)3 + 6 CH3MgBr → (NP(CH3)2)3 + 6 MgBrCl

Key point: Geminal substitution preferred initially, then non-geminal.


6. Polyphosphazenes (Inorganic Rubber)

[NPCl2]n + 2n NaOR → [NPRO2]n + 2n NaCl
  • When R = –OCH2CF3 or –OC6H5 → thermally stable, hydrophobic, flame-retardant elastomers
  • Remain flexible even at –70°C
  • Used as O-rings, gaskets, fuel hoses in aerospace & military
  • Biocompatible → used in drug delivery & tissue engineering
Most famous commercial name: Poly(difluorophosphazene) & Poly(aryloxyphosphazene)

7. Key Exam Points (Repeatedly Asked)

  • (NPCl2)3 is more stable than (NPCl2)4
  • Trimer has chair conformation in solid state
  • All Cl atoms are equivalent in (NPCl2)3
  • Phosphazenes are hydrolysed by water (slowly) but very rapidly by alkali
  • Unlike (SiO2)n, phosphazenes are flexible due to easy rotation about P–N bond
  • High thermal stability + low glass transition temperature → “Inorganic rubber”

Phosphazenes MCQs Asked in Previous Year Exams

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