Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2
Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2
Equation-2 gives eigen value −4 but not equation-1. So, Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2.
Share