Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2

Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2

Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2


Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2

Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2

Equation-2 gives eigen value −4 but not equation-1. So, Ψ = sin2x is not the eigen function of Operator d/dx but of d2/dx2.

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