CFSE for [CoCl6]-4 is 18000cm-1, CFSE for [CoCl4]-2 will be
A. 6000cm-1
B. 16000cm-1
C. 8000cm-1
D. 18000cm-1
[NEET Odisha 2019]
[CoCl6]-4 is octahedral complex while [CoCl4]-2 is tetrahedral complex.
We now that
Δtet = 4/9Δoct
putting the value of Δoct = 18000cm-1 we get-
Δtet = (4/9) x 18000cm-1 = 8000cm-1
Thus, the CFSE for [CoCl4]-2 will be 8000cm-1
So, the correct option is C.